Solve the following pair of linear equations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given equations are: $1) \, y + x = 5 \implies y = 5 - x$ $2) \, y - x = 9 \implies y = 9 + x$ To plot the graph, we find points for each line: Fo

Vedclass · Accepted Answer

$(-2, 7)$

Vedclass · Answer

(A) Given equations are: $1) \, y + x = 5 \implies y = 5 - x$ $2) \, y - x = 9 \implies y = 9 + x$ To plot the graph, we find points for each line: For $y = 5 - x$: If $x = 0, y = 5$; If $x = 5, y = 0$. Points are $(0, 5)$ and $(5, 0)$. For $y = 9 + x$: If $x = 0, y = 9$; If $x = -9, y = 0$. Points are $(0, 9)$ and $(-9, 0)$. Solving algebraically for intersection: Adding the two equations: $(y + x) + (y - x) = 5 + 9 \implies 2y = 14 \implies y = 7$. Substituting $y = 7$ in $y + x = 5$: $7 + x = 5 \implies x = -2$. The point of intersection is $(-2, 7)$.

Solve the following pair of linear equations in two variables using the graphical method: $y + x = 5$ and $y - x = 9$.

Similar Questions

Comparing the equation $x=4$ with the standard form $ax+by+c=0$,we get $b=\ldots \ldots \ldots$

The graph of the equation $\ldots \ldots \ldots \ldots$ is parallel to the $X$-axis.

Romila went to a stationery shop and purchased $2$ pencils and $3$ erasers for ₹ $9$. Her friend Sonali saw the new variety of pencils and erasers with Romila,and she also bought $4$ pencils and $6$ erasers of the same kind for ₹ $18$. Represent this situation algebraically and graphically.

Do the equations $4x + 3y - 1 = 5$ and $12x + 9y = 15$ represent a pair of coincident lines? Justify your answer.

The line represented by $x=7$ is parallel to the $x$-axis. Justify whether the statement is true or not.

Vedclass Test Series

Exam Paper Generator

Online Exam Module